Optimal. Leaf size=195 \[ -\frac {3 \sin (a+x (b-3 d)-3 c)}{32 (b-3 d)}+\frac {9 \sin (a+x (b-d)-c)}{32 (b-d)}+\frac {\sin (3 (a-c)+3 x (b-d))}{96 (b-d)}-\frac {3 \sin (3 a+x (3 b-d)-c)}{32 (3 b-d)}-\frac {9 \sin (a+x (b+d)+c)}{32 (b+d)}-\frac {\sin (3 (a+c)+3 x (b+d))}{96 (b+d)}+\frac {3 \sin (3 a+x (3 b+d)+c)}{32 (3 b+d)}+\frac {3 \sin (a+x (b+3 d)+3 c)}{32 (b+3 d)} \]
[Out]
________________________________________________________________________________________
Rubi [A] time = 0.13, antiderivative size = 195, normalized size of antiderivative = 1.00, number of steps used = 10, number of rules used = 2, integrand size = 17, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.118, Rules used = {4569, 2637} \[ -\frac {3 \sin (a+x (b-3 d)-3 c)}{32 (b-3 d)}+\frac {9 \sin (a+x (b-d)-c)}{32 (b-d)}+\frac {\sin (3 (a-c)+3 x (b-d))}{96 (b-d)}-\frac {3 \sin (3 a+x (3 b-d)-c)}{32 (3 b-d)}-\frac {9 \sin (a+x (b+d)+c)}{32 (b+d)}-\frac {\sin (3 (a+c)+3 x (b+d))}{96 (b+d)}+\frac {3 \sin (3 a+x (3 b+d)+c)}{32 (3 b+d)}+\frac {3 \sin (a+x (b+3 d)+3 c)}{32 (b+3 d)} \]
Antiderivative was successfully verified.
[In]
[Out]
Rule 2637
Rule 4569
Rubi steps
\begin {align*} \int \sin ^3(a+b x) \sin ^3(c+d x) \, dx &=\int \left (-\frac {3}{32} \cos (a-3 c+(b-3 d) x)+\frac {9}{32} \cos (a-c+(b-d) x)+\frac {1}{32} \cos (3 (a-c)+3 (b-d) x)-\frac {3}{32} \cos (3 a-c+(3 b-d) x)-\frac {9}{32} \cos (a+c+(b+d) x)-\frac {1}{32} \cos (3 (a+c)+3 (b+d) x)+\frac {3}{32} \cos (3 a+c+(3 b+d) x)+\frac {3}{32} \cos (a+3 c+(b+3 d) x)\right ) \, dx\\ &=\frac {1}{32} \int \cos (3 (a-c)+3 (b-d) x) \, dx-\frac {1}{32} \int \cos (3 (a+c)+3 (b+d) x) \, dx-\frac {3}{32} \int \cos (a-3 c+(b-3 d) x) \, dx-\frac {3}{32} \int \cos (3 a-c+(3 b-d) x) \, dx+\frac {3}{32} \int \cos (3 a+c+(3 b+d) x) \, dx+\frac {3}{32} \int \cos (a+3 c+(b+3 d) x) \, dx+\frac {9}{32} \int \cos (a-c+(b-d) x) \, dx-\frac {9}{32} \int \cos (a+c+(b+d) x) \, dx\\ &=-\frac {3 \sin (a-3 c+(b-3 d) x)}{32 (b-3 d)}+\frac {9 \sin (a-c+(b-d) x)}{32 (b-d)}+\frac {\sin (3 (a-c)+3 (b-d) x)}{96 (b-d)}-\frac {3 \sin (3 a-c+(3 b-d) x)}{32 (3 b-d)}-\frac {9 \sin (a+c+(b+d) x)}{32 (b+d)}-\frac {\sin (3 (a+c)+3 (b+d) x)}{96 (b+d)}+\frac {3 \sin (3 a+c+(3 b+d) x)}{32 (3 b+d)}+\frac {3 \sin (a+3 c+(b+3 d) x)}{32 (b+3 d)}\\ \end {align*}
________________________________________________________________________________________
Mathematica [A] time = 1.66, size = 177, normalized size = 0.91 \[ \frac {1}{96} \left (-\frac {9 \sin (a+b x-3 c-3 d x)}{b-3 d}+\frac {27 \sin (a+b x-c-d x)}{b-d}+\frac {\sin (3 (a+b x-c-d x))}{b-d}-\frac {9 \sin (3 a+3 b x-c-d x)}{3 b-d}+\frac {9 \sin (3 a+3 b x+c+d x)}{3 b+d}+\frac {9 \sin (a+b x+3 c+3 d x)}{b+3 d}-\frac {27 \sin (a+x (b+d)+c)}{b+d}-\frac {\sin (3 (a+x (b+d)+c))}{b+d}\right ) \]
Antiderivative was successfully verified.
[In]
[Out]
________________________________________________________________________________________
fricas [A] time = 0.59, size = 291, normalized size = 1.49 \[ -\frac {{\left ({\left (63 \, b^{4} d - 88 \, b^{2} d^{3} + 9 \, d^{5} - {\left (9 \, b^{4} d - 82 \, b^{2} d^{3} + 9 \, d^{5}\right )} \cos \left (b x + a\right )^{2}\right )} \cos \left (d x + c\right )^{3} - 3 \, {\left (21 \, b^{4} d - 70 \, b^{2} d^{3} + 9 \, d^{5} - {\left (3 \, b^{4} d - 28 \, b^{2} d^{3} + 9 \, d^{5}\right )} \cos \left (b x + a\right )^{2}\right )} \cos \left (d x + c\right )\right )} \sin \left (b x + a\right ) - {\left ({\left (9 \, b^{5} - 88 \, b^{3} d^{2} + 63 \, b d^{4}\right )} \cos \left (b x + a\right )^{3} - {\left ({\left (9 \, b^{5} - 82 \, b^{3} d^{2} + 9 \, b d^{4}\right )} \cos \left (b x + a\right )^{3} - 3 \, {\left (9 \, b^{5} - 28 \, b^{3} d^{2} + 3 \, b d^{4}\right )} \cos \left (b x + a\right )\right )} \cos \left (d x + c\right )^{2} - 3 \, {\left (9 \, b^{5} - 70 \, b^{3} d^{2} + 21 \, b d^{4}\right )} \cos \left (b x + a\right )\right )} \sin \left (d x + c\right )}{3 \, {\left (9 \, b^{6} - 91 \, b^{4} d^{2} + 91 \, b^{2} d^{4} - 9 \, d^{6}\right )}} \]
Verification of antiderivative is not currently implemented for this CAS.
[In]
[Out]
________________________________________________________________________________________
giac [A] time = 0.18, size = 181, normalized size = 0.93 \[ -\frac {\sin \left (3 \, b x + 3 \, d x + 3 \, a + 3 \, c\right )}{96 \, {\left (b + d\right )}} + \frac {3 \, \sin \left (3 \, b x + d x + 3 \, a + c\right )}{32 \, {\left (3 \, b + d\right )}} - \frac {3 \, \sin \left (3 \, b x - d x + 3 \, a - c\right )}{32 \, {\left (3 \, b - d\right )}} + \frac {\sin \left (3 \, b x - 3 \, d x + 3 \, a - 3 \, c\right )}{96 \, {\left (b - d\right )}} + \frac {3 \, \sin \left (b x + 3 \, d x + a + 3 \, c\right )}{32 \, {\left (b + 3 \, d\right )}} - \frac {9 \, \sin \left (b x + d x + a + c\right )}{32 \, {\left (b + d\right )}} + \frac {9 \, \sin \left (b x - d x + a - c\right )}{32 \, {\left (b - d\right )}} - \frac {3 \, \sin \left (b x - 3 \, d x + a - 3 \, c\right )}{32 \, {\left (b - 3 \, d\right )}} \]
Verification of antiderivative is not currently implemented for this CAS.
[In]
[Out]
________________________________________________________________________________________
maple [A] time = 2.02, size = 184, normalized size = 0.94 \[ -\frac {3 \sin \left (a -3 c +\left (b -3 d \right ) x \right )}{32 \left (b -3 d \right )}+\frac {9 \sin \left (a -c +\left (b -d \right ) x \right )}{32 \left (b -d \right )}-\frac {9 \sin \left (a +c +\left (b +d \right ) x \right )}{32 \left (b +d \right )}+\frac {3 \sin \left (a +3 c +\left (b +3 d \right ) x \right )}{32 \left (b +3 d \right )}+\frac {\sin \left (\left (3 b -3 d \right ) x +3 a -3 c \right )}{96 b -96 d}-\frac {3 \sin \left (3 a -c +\left (3 b -d \right ) x \right )}{32 \left (3 b -d \right )}+\frac {3 \sin \left (3 a +c +\left (3 b +d \right ) x \right )}{32 \left (3 b +d \right )}-\frac {\sin \left (\left (3 b +3 d \right ) x +3 a +3 c \right )}{96 \left (b +d \right )} \]
Verification of antiderivative is not currently implemented for this CAS.
[In]
[Out]
________________________________________________________________________________________
maxima [B] time = 0.57, size = 2612, normalized size = 13.39 \[ \text {result too large to display} \]
Verification of antiderivative is not currently implemented for this CAS.
[In]
[Out]
________________________________________________________________________________________
mupad [B] time = 4.31, size = 997, normalized size = 5.11 \[ {\mathrm {e}}^{a\,3{}\mathrm {i}-c\,1{}\mathrm {i}+b\,x\,3{}\mathrm {i}-d\,x\,1{}\mathrm {i}}\,\left (\frac {-9\,b^3-3\,b^2\,d+9\,b\,d^2+3\,d^3}{b^4\,576{}\mathrm {i}-b^2\,d^2\,640{}\mathrm {i}+d^4\,64{}\mathrm {i}}+\frac {{\mathrm {e}}^{-a\,6{}\mathrm {i}-b\,x\,6{}\mathrm {i}}\,\left (-9\,b^3+3\,b^2\,d+9\,b\,d^2-3\,d^3\right )}{b^4\,576{}\mathrm {i}-b^2\,d^2\,640{}\mathrm {i}+d^4\,64{}\mathrm {i}}-\frac {{\mathrm {e}}^{-a\,2{}\mathrm {i}-b\,x\,2{}\mathrm {i}}\,\left (-81\,b^3-81\,b^2\,d+9\,b\,d^2+9\,d^3\right )}{b^4\,576{}\mathrm {i}-b^2\,d^2\,640{}\mathrm {i}+d^4\,64{}\mathrm {i}}-\frac {{\mathrm {e}}^{-a\,4{}\mathrm {i}-b\,x\,4{}\mathrm {i}}\,\left (-81\,b^3+81\,b^2\,d+9\,b\,d^2-9\,d^3\right )}{b^4\,576{}\mathrm {i}-b^2\,d^2\,640{}\mathrm {i}+d^4\,64{}\mathrm {i}}\right )-{\mathrm {e}}^{a\,3{}\mathrm {i}+c\,1{}\mathrm {i}+b\,x\,3{}\mathrm {i}+d\,x\,1{}\mathrm {i}}\,\left (\frac {-9\,b^3+3\,b^2\,d+9\,b\,d^2-3\,d^3}{b^4\,576{}\mathrm {i}-b^2\,d^2\,640{}\mathrm {i}+d^4\,64{}\mathrm {i}}+\frac {{\mathrm {e}}^{-a\,6{}\mathrm {i}-b\,x\,6{}\mathrm {i}}\,\left (-9\,b^3-3\,b^2\,d+9\,b\,d^2+3\,d^3\right )}{b^4\,576{}\mathrm {i}-b^2\,d^2\,640{}\mathrm {i}+d^4\,64{}\mathrm {i}}-\frac {{\mathrm {e}}^{-a\,2{}\mathrm {i}-b\,x\,2{}\mathrm {i}}\,\left (-81\,b^3+81\,b^2\,d+9\,b\,d^2-9\,d^3\right )}{b^4\,576{}\mathrm {i}-b^2\,d^2\,640{}\mathrm {i}+d^4\,64{}\mathrm {i}}-\frac {{\mathrm {e}}^{-a\,4{}\mathrm {i}-b\,x\,4{}\mathrm {i}}\,\left (-81\,b^3-81\,b^2\,d+9\,b\,d^2+9\,d^3\right )}{b^4\,576{}\mathrm {i}-b^2\,d^2\,640{}\mathrm {i}+d^4\,64{}\mathrm {i}}\right )-{\mathrm {e}}^{a\,3{}\mathrm {i}-c\,3{}\mathrm {i}+b\,x\,3{}\mathrm {i}-d\,x\,3{}\mathrm {i}}\,\left (\frac {-b^3-b^2\,d+9\,b\,d^2+9\,d^3}{b^4\,192{}\mathrm {i}-b^2\,d^2\,1920{}\mathrm {i}+d^4\,1728{}\mathrm {i}}+\frac {{\mathrm {e}}^{-a\,6{}\mathrm {i}-b\,x\,6{}\mathrm {i}}\,\left (-b^3+b^2\,d+9\,b\,d^2-9\,d^3\right )}{b^4\,192{}\mathrm {i}-b^2\,d^2\,1920{}\mathrm {i}+d^4\,1728{}\mathrm {i}}-\frac {{\mathrm {e}}^{-a\,2{}\mathrm {i}-b\,x\,2{}\mathrm {i}}\,\left (-9\,b^3-27\,b^2\,d+9\,b\,d^2+27\,d^3\right )}{b^4\,192{}\mathrm {i}-b^2\,d^2\,1920{}\mathrm {i}+d^4\,1728{}\mathrm {i}}-\frac {{\mathrm {e}}^{-a\,4{}\mathrm {i}-b\,x\,4{}\mathrm {i}}\,\left (-9\,b^3+27\,b^2\,d+9\,b\,d^2-27\,d^3\right )}{b^4\,192{}\mathrm {i}-b^2\,d^2\,1920{}\mathrm {i}+d^4\,1728{}\mathrm {i}}\right )+{\mathrm {e}}^{a\,3{}\mathrm {i}+c\,3{}\mathrm {i}+b\,x\,3{}\mathrm {i}+d\,x\,3{}\mathrm {i}}\,\left (\frac {-b^3+b^2\,d+9\,b\,d^2-9\,d^3}{b^4\,192{}\mathrm {i}-b^2\,d^2\,1920{}\mathrm {i}+d^4\,1728{}\mathrm {i}}+\frac {{\mathrm {e}}^{-a\,6{}\mathrm {i}-b\,x\,6{}\mathrm {i}}\,\left (-b^3-b^2\,d+9\,b\,d^2+9\,d^3\right )}{b^4\,192{}\mathrm {i}-b^2\,d^2\,1920{}\mathrm {i}+d^4\,1728{}\mathrm {i}}-\frac {{\mathrm {e}}^{-a\,2{}\mathrm {i}-b\,x\,2{}\mathrm {i}}\,\left (-9\,b^3+27\,b^2\,d+9\,b\,d^2-27\,d^3\right )}{b^4\,192{}\mathrm {i}-b^2\,d^2\,1920{}\mathrm {i}+d^4\,1728{}\mathrm {i}}-\frac {{\mathrm {e}}^{-a\,4{}\mathrm {i}-b\,x\,4{}\mathrm {i}}\,\left (-9\,b^3-27\,b^2\,d+9\,b\,d^2+27\,d^3\right )}{b^4\,192{}\mathrm {i}-b^2\,d^2\,1920{}\mathrm {i}+d^4\,1728{}\mathrm {i}}\right ) \]
Verification of antiderivative is not currently implemented for this CAS.
[In]
[Out]
________________________________________________________________________________________
sympy [F(-1)] time = 0.00, size = 0, normalized size = 0.00 \[ \text {Timed out} \]
Verification of antiderivative is not currently implemented for this CAS.
[In]
[Out]
________________________________________________________________________________________